Jawapan Buku Teks Fizik Tingkatan - 4 Kssm Aktiviti 13 Work Work

GPE = m × g × h = 5 kg × 9.8 m/s^2 × 2 m = 98 J

Solution:

Work done = m × g × h = 100 kg × 9.8 m/s^2 × 5 m = 4900 J GPE = m × g × h = 5 kg × 9

Efficiency = (Work done / Energy input) × 100% = (980 J / 2000 J) × 100% = 49% If the machine takes 5 seconds to lift

KE = ½ × m × v^2 = ½ × 5 kg × (2 m/s)^2 = 10 J calculate its efficiency.

A 5 kg object is lifted to a height of 2 m above the ground. Calculate its gravitational potential energy.

A machine requires an input energy of 2000 J to lift a 50 kg load to a height of 2 m. If the machine takes 5 seconds to lift the load, calculate its efficiency.

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